T H E E L E M E N T S |
Book VI Proposition 18 | |
Again, on the straight line BG, and at the points B, G on it, let let the angle BGH be constructed equal to the angle at DFE, and the angle GBH equal to the angle FDE. [I.23] Therefore the remaining angle E is equal to the remaining angle at H; [I.32] therefore the triangle FDE is equiangular with the triangle GBH; therefore, proportionally, as FD is to GB, so is FE to GH, and ED to HB. [VI.4] |
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