P
Y
T
H
A
G
O
R
A
S
   Geometric Demonstration that the Diagonal and Side of a Square are Incommensurable
On AC
    let B1C have been taken equal to BC,
    let B1C1 have been drawn perpendicular to AC,
and
    let C1C have been joined.
Previous Page   Return to Pythagoras' Page   Next Page