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PR is equal to OS,
let
QB be added to each;
therefore
the whole PB is equal to the whole OB.
But
OB is equal to TE, since the side AE is also equal to the side EB; [I.36]
therefore
TE is also equal to PB.
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T H E E L E M E N T S |
Book VI Proposition 28 | |
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And, since PR is equal to OS, let QB be added to each; therefore the whole PB is equal to the whole OB. But OB is equal to TE, since the side AE is also equal to the side EB; [I.36] therefore TE is also equal to PB. |
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