T H E E L E M E N T S |
Book VI Proposition 27 | |
Therefore, GA has the same ratio to each of the straight lines AK, AE. Therefore AE is equal to AK [V.9], the less to the greater: which is impossible. Therefore ABCD cannot but be about the same diameter with AF; Therefore the parallelogram ABCD is about the same diameter with the parallelogram AF. |
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