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CF is equal to FE, [I.43]
and
FB is common,
therefore
the whole CH is equal to the whole KE.
But
CH is equal to CG, since AC is also equal to EK. [I.36]
Therefore
CG is also equal to EK.
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T H E E L E M E N T S |
Book VI Proposition 27 | |
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Then, since CF is equal to FE, [I.43] and FB is common, therefore the whole CH is equal to the whole KE. But CH is equal to CG, since AC is also equal to EK. [I.36] Therefore CG is also equal to EK. |
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