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Book VI   Proposition 25
Therefore also,
    as the triangle ABC is to the triangle KGH,
    so is the parallelogram BE to the parallelogram EF;
therefore, aternately,
    as the triangle ABC is to the parallelogram BE,
    so is the triangle KGH to the parallelogram EF. [V.16]

But
    the triangle ABC is also equal to the parallelogram BE;
therefore
    the triangle KGH is also equal to the parallelogram EF.
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