T H E E L E M E N T S |
Book VI Proposition 25 | |
Therefore also, as the triangle ABC is to the triangle KGH, so is the parallelogram BE to the parallelogram EF; therefore, aternately, as the triangle ABC is to the parallelogram BE, so is the triangle KGH to the parallelogram EF. [V.16] But the triangle ABC is also equal to the parallelogram BE; therefore the triangle KGH is also equal to the parallelogram EF. |
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