|Book VI Proposition 25|
Let there be applied to BC
the parallelogram BE equal to the triangle ABC, [I.44]
and to CE
the parallelogram CM equal to D and in the angle FCE which is equal to the angle CBL. [I.45]
BC is in a straight line with CF, and LE with EM.
let GH be taken a mean proportional to BC, CF [VI.13],
on GH let KGH be described similar and similarly situated to ABC.
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