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the angle ABC is equal to the angle FGH,
and
as AB is to BC, so is FG to GH,
the triangle ABC is equiangular with the triangle EGH; [VI.6]
therefore
the angle BAC is equal to the angle GFH,
and
the angle BCA to the angle GHF.
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T H E E L E M E N T S |
Book VI Proposition 20 | |
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Then since, because of the equiangularity of the polygons, the angle ABC is equal to the angle FGH, and as AB is to BC, so is FG to GH, the triangle ABC is equiangular with the triangle EGH; [VI.6] therefore the angle BAC is equal to the angle GFH, and the angle BCA to the angle GHF. |
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