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FD has been drawn parallel to BC, one of the sides of the triangle ABC,
therefore, proportionallly,
as CD is to DA,
so is BF to FA. [VI.2]
But
CD is double of DA;
therefore
BF is also double of FA;
therefore;
BA is triple of AF.
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T H E E L E M E N T S |
Book VI Proposition 9 | |
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Then, since FD has been drawn parallel to BC, one of the sides of the triangle ABC, therefore, proportionallly, as CD is to DA, so is BF to FA. [VI.2] But CD is double of DA; therefore BF is also double of FA; therefore; BA is triple of AF. |
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