T H E E L E M E N T S |
Book VI Proposition 7 | |
For, with the same construction, we can prove similarly that BC is equal to BG; so that the angle at C is also equal to the angle BGC. [I.5] But the angle at C is not less than a right angle; therefore neither is the angle BCG less than a right angle. Thus in the triangle BGC the two angles are not less than two right angles: which is impossible. [I.17] |
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