T H E E L E M E N T S |
Book VI Proposition 7 | |
Therefore the triangle ABG is equianglar with the triangle DEF. Therefore as DE is to BG, so is DE to EF. [VI.4] But as DE is to EF, so by hypothesis is AB to BC; therefore AB has the same ratio to each of the straight lines BC, BG; [V.11] therefore BC is equal to BG, [V.9] so that the angle at C is also equal to the angle BGC. [I.5] |
||
Previous Page Return to Propositions Next Page |