T H E E L E M E N T S |
Book VI Proposition 6 | |
Therefore the angle DFG is equal to the angle DFE, and the angle DGF to the angle DEF. But the angle DFG is equal to the angle ACB; therefore the angle ACB is equal to the angle DFE. And, by hypothesis, the angle BAC is also equal to the angle EDF; therefore the remaining angle at B is also equal to the ramaining angle at E; [I.32] therefore the triangle ABC is equiangular with the triangle DEF. |
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