T H E E L E M E N T S |
Book VI Proposition 4 | |
And since AC has been drawn parallel to FE one side of the triangle FBE, therefore, as BA is to AF, so is BC to CE. [VI.2] But AF is equal to CD; therefore, as BA is to CD, so is BC to CE, and alternately, as AB is to BC, so is DC to CE. [V.16] |
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