Then, since
CB, BG, GH are equal to one another,
the triangles ABC, AGB, AHG are also equal to one another. [I.38]
Therefore
whatever multiple the base HC is of the base CD,
that multiple also is the triangle AHC of the triangle ABC.
For the same reason,
Whatever multiple the base LC is of the base CD,
that multiple also is the triangle ALC of the triangle ACD;
and,
if the base HC is equal to the base CL,
the triangle AHC is also equal to the triangle ACL, [I.38]
if the base HC is in excess of the base CL,
the triangle AHC is also in excess of the triangle ACL,
and
if less, less.

