|Book IV Proposition 15|
I say next that it is also equiangular.
the circumference FA is equal to the circumference ED,
let the circumference ABCD be added to each;
the whole circumference FABCD is equal to the whole circumference ABCDE;.
the angle FED stands on the circumference FABCD, and the angle AFE on the circumference ABCDE;
the angle AFE is equal to the angle DEF. [III.27]
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