T H E E L E M E N T S |
Book IV Proposition 12 | |
And, since the angle FCK is right, therefore the square on FK is equal to the squares on FC, CK. [I.47] For the same reason the square on FK is also equal to the squares on FB, BK; so that the squares on FC, CK are equal to the squares on FB, BK, of which the square on FC is equal to the square on FB; therefore The square on CK which remains is equal to the square on BK. |
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