T H E E L E M E N T S |
Book IV Proposition 11 | |
I say next that it is also equiangular. For, since the circumference AB is equal to the circumference DE, let BCD be added to each; therefore the whole circumference ABCD is equal to the whole circumference BCDE. And the angle AED stands on the circumference ABCD, and the angle BAE on the circumference BCDE; therefore the angle BAE is also equal to the angle AED. [III.27] |
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