|Book IV Proposition 11|
I say next that it is also equiangular.
the circumference AB is equal to the circumference DE,
let BCD be added to each;
the whole circumference ABCD is equal to the whole circumference BCDE.
the angle AED stands on the circumference ABCD, and the angle BAE on the circumference BCDE;
the angle BAE is also equal to the angle AED. [III.27]
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