T H E E L E M E N T S |
Book III Proposition 36 | |
But the squares on EB, BD are equal to the square on ED, for the angle EFC is right; [I.47] therefore the rectangle AD, DC together with the square on EB is equal to the squares on EB, BD. Let the square on EB be subtracted form each; therefore the rectangle AD, DC which remains is equal to the square on DB. Being what it was required to prove |
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