T H E E L E M E N T S |
Book III Proposition 36 | |
Now, since the straight line AC has been bisected at the point F,
and CD added to it, the rectangle contained by AD, DC together with the square on FC is equal to the square on FD. [II.6] Let the square on FE be added to each; therefore the rectangle AD, DC together with the squares on CF, FE is equal to the squares on FD, FE. |
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