T H E E L E M E N T S |
Book III Proposition 35 | |
But the square on FE is equal to the squares on EG, GF, and the square on FC is equal to the squares on CG, GF; [I.47] therefore The rectangle AE, EC together with the square on FE is equal to the square on FC. And FC is equal to FB; therefore The rectangle AE, EC together with the square on FE is equal to the square on FB. |
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