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S		 Book III   Proposition 35
Next let AC, DB not be through the center;
    let the center of ABCD be taken, and let it be F;
from F
    let FG, FH be drawn perpendicular to the straight lines AC, DB,
and
    let FB, FC, FE be joined.

Then, since a straight line FG throught the center cuts a straight line AC not through the center at right angles,
it also bisects it; [III.3]
therefore
    AG is equal to GC.
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