|Book III Proposition 35|
Next let AC, DB not be through the center;
let the center of ABCD be taken, and let it be F;
let FG, FH be drawn perpendicular to the straight lines AC, DB,
let FB, FC, FE be joined.
Then, since a straight line FG throught the center cuts a straight line AC not through the center at right angles,
AG is equal to GC.
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