T H E E L E M E N T S |
Book III Proposition 35 | |
Next let AC, DB not be through the center; let the center of ABCD be taken, and let it be F; from F let FG, FH be drawn perpendicular to the straight lines AC, DB, and let FB, FC, FE be joined. Then, since a straight line FG throught the center cuts a straight line AC not through the center at right angles, AG is equal to GC. |
||
Previous Page Return to Propositions Next Page |