|Book III Proposition 33|
AB has been drawn across from the point of contact at A; therefore
the angle DAB is equal to the angle constructed in the alternate segment AHB of the circle. [III.32]
the angle BAD is equal to the angle at C.
the angle in the segment AHB is also equal to the angle at C.
on the given straight line AB the segment AHB of a circle has been described admitting an angle equal to the angle at C.
Being what it was required to do.
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