T H E E L E M E N T S |
Book III Proposition 32 | |
Therefore, if a straight line EF touch the circle ABCD at the point B, and from B there is drawn across, in the circle ABCD, a straight line cutting it, then the angle FBD is equal to the angle constructed in the segment BAD, and the angle EBD is equal to the angle constructed in the segment DCB. Being what it was required to prove. |
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