|Book III Proposition 29|
the circumference BGC is equal to the circumference EHF,
the angle BKC is also equal to the angle ELF. [III.27]
And, since the circles ABC, DEF are equal,
the two sides BK, KC are equal to the two sides EL, LF; and they contain equal angles;
the base BC is equal to the base EF. [I.4]
Being what it was required to prove.
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