T H E E L E M E N T S |
Book III Proposition 28 | |
For let the centers K, L of the circles be taken, and let AK, KB, DL, LE be joined. Now, since the circles are equal, the two sides AK, KB are equal to the two sides DL, LE; and the base AB is equal to the base DE; therefore the angle AKB is equal to the angle DLE. [I.8] |
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