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I say that the angle BGC is equal to the angle EHF and the angle BAC is equal to the angle EDF.
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T H E E L E M E N T S |
Book III Proposition 27 | |
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For in equal circles ABC, DEF,
on equal circumferences BC, EF,
let the angles BGC, EHF stand at the centers G, H,
and the angles BAC, EDF at the circumferences; I say that the angle BGC is equal to the angle EHF and the angle BAC is equal to the angle EDF. |
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