T H E E L E M E N T S |
Book III Proposition 25 | |
The line EA was proved equal to each of EB, EC; therefore the three straight lines EA, EB, EC are equal to one another. Therefore the circle drawn with center E and distance one of the straight lines EA, EB, EC will also pass through the remaining points and will have been completed. [III.9] Therefore, given a segment of a circle, the complete circle has been described. And it is manifest that the segment ABC is less than a semicircle, because the center E happens to be outside it. |
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