T H E E L E M E N T S |
Book III Proposition 24 | |
For, if the straight line AB coincide with CD but the segment AEB
does not coincede with CFD, it will either fall within it [as CGD], or outside it: which is impossible [III.23] or it will fall awry, as CGD, and a circle cuts a circle at more points than two: which is impossible. [III.10] therefore, if the straight line AB be applied to CD, the segment AEB will not fail to coincide with CFD also; Being what it was required to prove. |
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