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Book III   Proposition 17
For, since E is the center of the circles BCD, AFG,
    EA is equal to EF, and ED to EB;
therefore
    the two sides AE, EB are equal to the two sides FE, ED: and they contain a common angle, the angle at E;
therefore
    the base DF is equal to the base BA, and the triangle EDF is equal to the triangle EBA, and the remaining angles to the remaining angles; [I.4] therefore
the angle EDF is equal to the angle EBA.

But
    the angle EDF is right;
therefore
    the angle EBA is also right.
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