T H E E L E M E N T S |
Book III Proposition 17 | |
For, since E is the center of the circles BCD, AFG, EA is equal to EF, and ED to EB; therefore the two sides AE, EB are equal to the two sides FE, ED: and they contain a common angle, the angle at E; therefore the base DF is equal to the base BA, and the triangle EDF is equal to the triangle EBA, and the remaining angles to the remaining angles; [I.4] therefore But the angle EDF is right; therefore the angle EBA is also right. |
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