|Book III Proposition 15|
For from the center E
let EH, EK be drawn perpendicular to BC, FG.
Then, since BC is nearer to the center and FG more remote, EK is greater than EH. [III.Def.5]
Let EL be made equal to EH,
let LM be drawn at right angles to EK and carried through to N,
let ME, EN, FE, EG be joined.
|Previous Page Return to Propositions Next Page|