H
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let EH, EK be drawn perpendicular to BC, FG.
Then, since BC is nearer to the center and FG more remote, EK is greater than EH. [III.Def.5]
Let EL be made equal to EH,
through L
let LM be drawn at right angles to EK and carried through to N,
and
let ME, EN, FE, EG be joined.
