T H E E L E M E N T S |
Book III Proposition 15 | |
For from the center E let EH, EK be drawn perpendicular to BC, FG. Then, since BC is nearer to the center and FG more remote, EK is greater than EH. [III.Def.5] Let EL be made equal to EH, through L let LM be drawn at right angles to EK and carried through to N, and let ME, EN, FE, EG be joined. |
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