T H E E L E M E N T S |
Book III Proposition 14 | |
Then, since a straight line EF through the center cuts a straight line AB not through the center at right angles, it also bisects it. [III.3] Therefore AF is equal to FB; therefore AB is double of AF. For the same reason CD is also double of CG; and AB is equal to CD; therefore AF is also equal to CG. |
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