T H E E L E M E N T S |
Book III Proposition 10 | |
It was proved that the center of the circle ABC is on each of AC, NO. And the straight lines meet at no point except at P; therefore the point P is the center of the circle ABC. Similarly we can prove that P is also the center of the circle DEF; therefore the two circles ABC, DEF which cut one another have the same center P: which is impossible. [III.5] |
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