T H E E L E M E N T S |
Book III Proposition 9 | |
Then, since AE is equal to EB, and ED is common, the two sides AE, ED are equal to the two sides BE, ED, and the base DF is equal to the base EF ; therefore the angle AED is equal to the angle BED. [I.8] Therefore each of the angles AED, BED is right; [I.Def.10] therefore GK cuts AB into two equal parts and at right angles. |
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