T H E E L E M E N T S |
Book III Proposition 8 | |
I say again that no other straight line equal to the straight line DL will fall on the circle
from the point D. For, if possible, let a straight line so fall, and let it be DN. Then, since DL is equal to DN, while DL is equal to DB, DB is also equal to DN, that is, the nearer to the least DG equal to the more remote: which was proved impossible. Therefore no more than two equal straight lines will fall on the circle ABC from the point D, one on eqch side of DG the least. Being what it was required to prove. |
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