H
E
E
L
E
M
E
N
T
S
For, if possible,
let a straight line so fall, and let it be DN.
Then, since
DL is equal to DN, while DL is equal to DB,
DB is also equal to DN,
that is, the nearer to the least DG equal to the more remote: which was proved impossible.
Therefore
no more than two equal straight lines will fall on the circle ABC from the point D, one on eqch side of DG the least.
Being what it was required to prove.
