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the two sides EM, MD are equal to the two sides FM, MD;
and
the angle EMD is greater than the angle FMD;
therefore
the base ED is greater than the base FD. [I.24]
Similarly we can prove that
FD is greater than CD.
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T H E E L E M E N T S |
Book III Proposition 8 | |
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Again, since ME is equal to MF, and MD is common, therefore the two sides EM, MD are equal to the two sides FM, MD; and the angle EMD is greater than the angle FMD; therefore the base ED is greater than the base FD. [I.24] Similarly we can prove that FD is greater than CD. |
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