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AM is equal to EM, let MD be added to each;
therefore
AD is equal to EM, MD.
But
EM, MD are greater than ED; [I.20]
therefore
AD is also greater then ED.
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T H E E L E M E N T S |
Book III Proposition 8 | |
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Then, since AM is equal to EM, let MD be added to each; therefore AD is equal to EM, MD. But EM, MD are greater than ED; [I.20] therefore AD is also greater then ED. |
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