H
E
E
L
E
M
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For, if possible, let FK so fall.
Then, since
FK is equal to FG and FH to FG,
FK is also equal to FH,
the nearer to the straight line through the center being thus equal to the more remote: which is impossible.
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T H E E L E M E N T S |
Book III Proposition 7 | |
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I say again that another straight line equal to FG will not
fall on the circle from the point F. For, if possible, let FK so fall. Then, since FK is equal to FG and FH to FG, FK is also equal to FH, the nearer to the straight line through the center being thus equal to the more remote: which is impossible. |
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