T H E E L E M E N T S |
Book III Proposition 7 | |
I say also that form the point F
only two equal straight lines will fall on the circle ABCD, one on each side of the diameter AD.
(continue) For on the straight line EF, and at the point E on it, let the angle FEH be constructed equal to the angle GEF, [I.23] and let FH be joined. Then, since GE is equal to EH, and EF is common, the two sides GE, EF are equal to the two sides HE, EF; and the angle GEF is equal to the angle HEF; therefore the base FH is equal to the base FG. [I.4] |
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