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Then, since in any triangle two sides are greater than the remaining one, [I.20]
BE, EF are greater than BF.
But
AE is equal to BE;
therefore
AF is greater than BF.
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T H E E L E M E N T S |
Book III Proposition 7 | |
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For
let BE, CE, GE be joined. Then, since in any triangle two sides are greater than the remaining one, [I.20] BE, EF are greater than BF. But AE is equal to BE; therefore AF is greater than BF. |
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