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each of FE, FB was proved equal to FC;
therefore
FE is also equal to FB,
Therefore
the point F is not the center of the circles ABC, CDE.
Being what it was required to prove.
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T H E E L E M E N T S |
Book III Proposition 6 | |
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Now, each of FE, FB was proved equal to FC; therefore FE is also equal to FB, Therefore the point F is not the center of the circles ABC, CDE. Being what it was required to prove. |
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