T
H
E

E
L
E
M
E
N
T
S		 Book II   Proposition 14
Then,
    since the straight line BF has been cut into equal segments at G, and unequal segments at E,

    the rectangle contained by BE, EF together with the square on EG
is equal to
    the square on GF. [II.5]


But
    GF is equal to GH;
therefore
    the rectangle BE, EF together with the square on GE is equal to the square on GH.
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