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the rectangle CF, FA is FK, for FA is equal to FG;
and
the square on AB is AD;
therefore
FK is equal to AD.
Let AK be subtracted from each;
therefore
FH which remains is equal to HD.
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T H E E L E M E N T S |
Book II Proposition 11 | |
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Now the rectangle CF, FA is FK, for FA is equal to FG; and the square on AB is AD; therefore FK is equal to AD. Let AK be subtracted from each; therefore FH which remains is equal to HD. |
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