T H E E L E M E N T S |
Book II Proposition 11 | |
But the squares on BA, AE are equal to the square on EB, for the angle at A is right; [I.47] therefore the rectangle CF, FA together with the square on AE is equal to the squares on BA, AE. Let the square on AE be subtracted form each; therefore the rectangle CF, FA which remains is equal to the square on AB. |
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