T H E E L E M E N T S |
Book II Proposition 10 | |
Again, since EF is equal to FG, the square on EF is also equal to the square on FG; therefore the squares on EF, FG are double of the square on EF. But the square on EG is equal to the squares EF, FG; [I.47] therefore the square on EG is double of the square on EF. And EF is equal to CD; [I.34] therefore the square on EG is double of the square on CD. |
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