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Book II   Proposition 10
Again, since EF is equal to FG,
    the square on EF is also equal to the square on FG;
therefore
    the squares on EF, FG are double of the square on EF.

But
    the square on EG is equal to the squares EF, FG; [I.47]
therefore
    the square on EG is double of the square on EF.
And
    EF is equal to CD; [I.34]
therefore
    the square on EG is double of the square on CD.
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