T H E E L E M E N T S |
Book II Proposition 6 | |
Let CM be added to each; therefore the whole AM is equal to the gnomon NOP . But AM is the rectangle AD, DB, for DM is equal to DB; therefore the gnomon NOP is also equal to the rectangle AD, DB. Let LG, which is equal to the square on BC, be added to each; therefore the rectangle contained by AD, DB and the square on CB are equal to the gnomon NOP and LG. |
||
Previous Page Return to Propositions Next Page |