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Book II   Proposition 6
Let
    CM be added to each;
therefore
    the whole AM is equal to the gnomon NOP .

But
    AM is the rectangle AD, DB, for DM is equal to DB;
therefore
    the gnomon NOP is also equal to the rectangle AD, DB.

Let
    LG, which is equal to the square on BC, be added to each;
therefore
    the rectangle contained by AD, DB and the square on CB are equal to the gnomon NOP and LG.
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