T H E E L E M E N T S |
Book II Proposition 5 | |
Let CH be added to each; therefore the whole AH is equal to the gnomon NOP . But AH is the rectangle AD, DB, for DH is equal to DB, therefore the gnomon NOP is also equal to the rectangle AD, DB. Let LG, which is equal to the square on CD, be added to each; therefore the gnomon NOP and LG are equal to the rectangle contained by AD, DB and the square on CD. |
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