H
E
E
L
E
M
E
N
T
S
CH be added to each;
therefore
the whole AH is equal to the gnomon NOP .
But
AH is the rectangle AD, DB, for DH is equal to DB,
therefore
the gnomon NOP is also equal to the rectangle AD, DB.
Let
LG, which is equal to the square on CD, be added to each;
therefore
the gnomon NOP and LG are equal to the rectangle contained by AD, DB and the square on CD.
