T H E E L E M E N T S |
Book I Proposition 44 | |
Then HLKF is a parallelogram, HK is its diameter, and AG, ME are parallelograms, and
LB, BF the so-called complements, about HK; therefore LB is equal to BF. [I.43] But, also, the triangle C is equal to BF; therefore LB is also equal to C. [C.N.1] And, since the angle ABM is equal to the angle GBE, [I.15] while the angle D to the angle GEB, the angle ABM is also equal to the angle D. |
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