T H E E L E M E N T S |
Book I Proposition 43 | |
Now, since the triangle AEK is equal to the triangle AHK, and KGC to KFC, the triangle AEK together with KGC is equal to the triangle AHK together with KFC. [C.N.2] And the whole triangle ABC is equal to the whole triangle ADC; therefore the complement BK which remains is equal to the complement KD which remains. [C.N.3] Being what it was required to prove. |
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