H
E
E
L
E
M
E
N
T
S
AD is also equal to EF; [C.N.1]
and
DE is common;
therefore
the whole AE is equal to the whole DF. [C.N.2]
|
T H E E L E M E N T S |
Book I Proposition 35 | |
|
For, since ABCD is a parallelogram,
AD is also equal to EF; [C.N.1] and DE is common; therefore the whole AE is equal to the whole DF. [C.N.2] |
|
|
| Previous Page Return to Propositions Next Page | ||