T H E E L E M E N T S |
Book I Proposition 34 | |
Therefore ABC, DCB are two triangles having the two angles ABC, BCA equal to the tow angles DCB, CBD respectively, and one side equal to one side, namely that adjoining the equal angles and common to both of them, BC; therefore they will also have the remaining sides equal to the remaining sides respectively, and the remaining angle to the remaining angle. [I.26] |
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